Question
A lottery ticket costs 2 dollars and the probability of winning is
0.1. If you win a lottery you receive 10 dollars, if you lose you
receive 0 dollars.
- Let \(X\) be a random variable that
represents your money gain after playing one round of lottery,
i.e. \(X=8\) if you win and \(X=-2\) if you lose. Find \(a\) and \(b\) such that \(X=a\cdot Y+b\) where \(Y\sim Bernoulli(p)\), i.e. \(Y\) is a Bernoulli random variable. What is
the value of \(p\)?
- Use the properties of expectation and variance to find \(E(X)\) and \(Var(X).\)
- If you play this lottery many-many times, do you think your average
money gain will be positive or negative?
- You decided to test your luck and bought 5 lottery tickets. Let
\(Z\) denote the number of winning
tickets. What is the expectation and variance of \(Z\)? Hint: use the link between Binomial
and Bernoulli random variables.
- What is the probability that at least one of these five tickets will
win?
- Let \(W\) be the average
money gain for your five tickets. Find the expectation and variance of
\(W\). Hint: use \(X_1, \ldots X_5\) to represent the money
gain of each ticket and find the formula that expresses \(W\) in terms of \(X_1,\ldots,X_5\)
- Find the chances that your average money gain is not negative,
i.e. \(P(W\geq0)\)? Is it higher than
50%? Hint: first find the formula that expresses \(W\) in terms of \(Z\).
- Now you decided to buy 100 tickets. Let \(W\) be the average money gain for
your 100 tickets. What is the expectation and variance of \(W\)?
- What is the approximate distribution of \(W\)?
- Use the answer in 9 to find the chances that your new average money
gain is not negative, i.e. \(P(W\geq0)\)? Is it higher than 50%?
- Use the 68–95–99.7 rule to find the interval \([c,d]\) that contains 95% of \(W\) values, i.e. such that \(P(c\leq W\leq d)=0.95.\)
- Use the 68–95–99.7 rule to find 2.5-th percentile for \(W\). In other words we need to find the
value \(t\) such that 2.5% of \(W\) values are less than \(t\), i.e. \(P(W\leq t)=0.025.\)
- Use standardization and the distribution table to find the 2.5-th
percentile for \(W\).